Edexcel International A Level Chemistry

Topic 5: Alkenes

The first unsaturated family. The C=C double bond fixes the shape of the molecule, gives geometric isomers, and makes alkenes react by addition, with a mechanism you can draw. Alkenes also join to make polymers.

The one idea

An alkene is a hydrocarbon with a C=C double bond. The double bond has two parts. The σ bond is like the single bonds of an alkane. The π bond is a weaker region of electron density above and below the plane of the bond. That π bond does three jobs. It stops rotation, which is why some alkenes have geometric isomers. It is electron-rich, so it is attacked by electrophiles. And it can break open, so an alkene undergoes addition with hydrogen, halogens, hydrogen halides and steam, and joins to other alkenes to make polymers.

Everything on these pages comes from that one bond. If you meet an alkene you have never seen, ask what the π bond will do.

Where to find things

Question Pages
What is an alkene, and what is the C=C bond made of? 1
Why can't the C=C rotate, and what are geometric isomers? 2 and 3
How do I name an isomer with E and Z? 4
What are the addition reactions of alkenes? 5 and 6
How do I test for an alkene? 7
What are electrophiles, carbocations and curly arrows? 8
How do I draw the mechanism for ethene with Br₂ or HBr? 9 and 10
Why is one product the major product? 11 and 12
How do alkenes make polymers, and how do I draw the repeat unit? 13 and 14
What are the problems with waste polymers? 15

How to use these notes

This topic has no core practical. The tests on page 7 (bromine water and acidified manganate(VII)) are described as practical boxes because the observations are common exam questions, but they are not listed practicals.

The skills that earn most marks here are drawing a mechanism with every curly arrow, dipole, charge and lone pair in the right place; naming E and Z isomers by priority; explaining the major product through carbocation stability; drawing a repeat unit with brackets and extension bonds; and giving observations (colour changes) and conditions for each reaction.

You need the naming and isomerism of Topic 4 and the covalent bonding of Topic 3 for this topic. Where an earlier topic is needed, the page says so.

Pages

  1. Alkenes and the double bond

    Alkenes are unsaturated hydrocarbons with general formula CₙH₂ₙ. Their C=C double bond is one σ bond plus one π bond, and the exposed π electrons make alkenes reactive.

    13 min 5.1

  2. Restricted rotation around C=C

    Groups can spin around a C–C single bond but not around a C=C double bond, because twisting would break the π bond. This locks the groups in place and gives geometric isomers.

    11 min 5.2

  3. Which alkenes have geometric isomers

    Geometric isomers need a C=C and two different groups on each carbon of it. Test each carbon of the double bond separately, then draw the isomers with 120° bond angles.

    13 min 5.2

  4. E–Z naming

    The E–Z system names geometric isomers by the priority of the groups on each carbon of the C=C. It works for every alkene with isomers, including those where cis and trans break down.

    14 min 5.3

  5. Adding hydrogen and halogens

    Alkenes react by addition. The π bond breaks and two atoms add across the C=C. Hydrogen with a nickel catalyst gives an alkane, and a halogen gives a di-substituted halogenoalkane.

    14 min 5.45.4(i)5.4(ii)

  6. Adding hydrogen halides and steam

    A hydrogen halide or steam adds H to one carbon of the C=C and X or OH to the other. A symmetrical alkene gives one product; an unsymmetrical alkene gives a major and a minor product.

    14 min 5.45.4(iii)5.4(iv)

  7. Oxidation to a diol and the bromine test

    Acidified potassium manganate(VII) oxidises a C=C to a diol and turns from purple to colourless. Bromine water is decolourised by a C=C, which makes it the test for an alkene.

    13 min 5.45.4(v)5.5

  8. Electrophiles and curly arrows

    The π bond is a region of high electron density, so it attracts electrophiles. Before drawing any mechanism, you need the rules for curly arrows and for how a bromine molecule can act as an electrophile.

    12 min 5.6

  9. The mechanism for ethene and bromine

    Bromine adds to ethene in two steps. The π electrons attack an induced Br⁺ end, forming a carbocation, and then a bromide ion attacks it. The products formed in bromine water are the evidence for two steps.

    14 min 5.65.6(i)

  10. The mechanism for ethene and hydrogen bromide

    Hydrogen bromide adds to ethene by the same two-step pattern as bromine. The difference is that H–Br is permanently polar, so no dipole has to be induced.

    11 min 5.65.6(i)

  11. Carbocation stability

    Carbocations are primary, secondary or tertiary according to the number of alkyl groups on the positive carbon. Alkyl groups release electrons, so tertiary is the most stable and primary the least.

    12 min 5.6

  12. The mechanism for propene and hydrogen bromide

    Propene can form a secondary or a primary carbocation with HBr. The secondary carbocation is more stable, so 2-bromopropane is the major product and 1-bromopropane the minor product.

    13 min 5.65.6(ii)

  13. Addition polymerisation

    Many alkene monomers join to make one long saturated chain. The C=C of each monomer becomes C–C, nothing else is formed, and the repeat unit is the part of the chain that repeats.

    12 min 5.7

  14. From monomer to repeat unit, and back

    Draw the repeat unit by turning the C=C into C–C and keeping the side groups in place. Work backwards by finding the two carbons of one unit and putting the C=C back.

    13 min 5.7

  15. Polymer disposal

    Addition polymers are unreactive and do not rot. Chemists develop biodegradable polymers, and remove the toxic gases from incineration by passing them through a base in a scrubber.

    11 min 5.85.8(i)5.8(ii)

Also in this topic: Topic 5 on a page

Spec checklist

Every point you can be examined on in this topic, and where it is explained. Tick them off as you go.

SpecYou should be able toWhere
5.1know the general formula of alkenes and understand that alkenes and cycloalkenes are hydrocarbons which are unsaturated (have a carbon-carbon double bond which consists of a σ bond and a π bond)Alkenes and cycloalkenes
The C=C bond: one σ bond and one π bond
5.2be able to explain geometric isomerism in terms of restricted rotation around a C=C double bond and the nature of the substituents on the carbon atomsRotation around single and double bonds
The same formula, two different molecules
The two conditions
Drawing and counting the isomers
5.3understand the E–Z naming system for geometric isomers and why it is necessary to use this when the cis- and trans- naming system breaks downcis and trans
The E–Z system
When cis and trans break down
5.4be able to describe the reactions of alkenes, limited to: (i) the addition of hydrogen, using a nickel catalyst, to form an alkane (ii) the addition of halogens to produce a di-substituted halogenoalkane (iii) the addition of hydrogen halides to produce mono-substituted halogenoalkanes (iv) the addition of steam, in the presence of an acid catalyst, to produce alcohols (v) oxidation of the double bond by acidified potassium manganate(VII) to produce a diolAlkenes react by addition
Hydrogen: hydrogenation
Halogens: a di-substituted halogenoalkane
Hydrogen halides
Steam
Oxidation by acidified manganate(VII)
5.4(i)(i) the addition of hydrogen, using a nickel catalyst, to form an alkaneHydrogen: hydrogenation
5.4(ii)(ii) the addition of halogens to produce a di-substituted halogenoalkaneHalogens: a di-substituted halogenoalkane
5.4(iii)(iii) the addition of hydrogen halides to produce mono-substituted halogenoalkanesHydrogen halides
5.4(iv)(iv) the addition of steam, in the presence of an acid catalyst, to produce alcoholsSteam
5.4(v)(v) oxidation of the double bond by acidified potassium manganate(VII) to produce a diolOxidation by acidified manganate(VII)
5.5know the qualitative test for a C=C double bond using bromine or bromine waterThe test for a C=C: bromine water
5.6be able to describe the mechanism (including diagrams), giving evidence where possible, of: (i) the electrophilic addition of bromine and hydrogen bromide to ethene (ii) the electrophilic addition of hydrogen bromide to propene. Use of the curly arrow notation is expected – the curly arrows should start from either a bond or from a lone pair of electrons. Knowledge of the relative stability of primary, secondary and tertiary carbocation intermediates is expected.Why alkenes attract electrophiles
Curly arrows
Step 1: the electrophile attacks the π bond
Step 2: the bromide ion attacks the carbocation
Evidence for the two-step mechanism
The mechanism
Primary, secondary and tertiary carbocations
Why tertiary is the most stable
Using it to predict a major product
Two routes from one alkene
Which route wins
5.6(i)(i) the electrophilic addition of bromine and hydrogen bromide to etheneStep 1: the electrophile attacks the π bond
Step 2: the bromide ion attacks the carbocation
The mechanism
5.6(ii)(ii) the electrophilic addition of hydrogen bromide to propeneTwo routes from one alkene
Which route wins
5.7be able to describe the addition polymerisation of alkenes and draw the repeat unit given the monomer, and vice versaMonomers and polymers
The repeat unit
From monomer to repeat unit
From repeat unit to monomer
5.8understand how chemists limit the problems caused by polymer disposal by: (i) developing biodegradable polymers (ii) removing toxic waste gases produced by the incineration of polymersWhy waste polymers are a problem
Biodegradable polymers
Incineration and toxic gases
5.8(i)(i) developing biodegradable polymersBiodegradable polymers
5.8(ii)(ii) removing toxic waste gases produced by the incineration of polymersIncineration and toxic gases