Edexcel International A Level Chemistry
Topic 13: Chemical Equilibria
The equilibrium constant turns the Unit 2 rule about which way an equilibrium shifts into a single number. You write it, calculate it, and learn that only temperature changes it, because of entropy.
The one idea
In Unit 2 you could say which way an equilibrium shifts when you change something. You could not say how far the reaction goes, or what stays the same. This topic gives every equilibrium one number, the equilibrium constant, .
comes from the concentrations (or partial pressures) at equilibrium, each raised to the power of its coefficient. At a fixed temperature it is a constant. Squeezing the mixture, adding a reactant or adding a catalyst does not change it. A change in concentration or pressure knocks the mixture away from , and the mixture moves back until it fits again.
Temperature is the one thing that changes , and the position of equilibrium then moves to match the new value. Entropy explains why: , and the surroundings term is the part that depends on temperature.
The four jobs
| Job | Pages |
|---|---|
| Write the expression for or , for homogeneous and heterogeneous systems, and give the units | Writing Kc to Units of K |
| Calculate and from equilibrium amounts, titration data and percentages dissociated | Kc from equilibrium amounts to Calculating Kp |
| Say how, if at all, concentration, pressure, a catalyst and temperature affect the position and the value of | What changes K to Temperature changes K |
| Explain the effect of temperature with entropy, and use the size of to predict how far a reaction goes | Entropy and K and How far does it go |
What you need first
- Dynamic equilibrium and Le Chatelier's principle from the Unit 2 kinetics and equilibria topic. This topic extends them.
- Amount of substance: moles, concentration in mol dm⁻³, and gas calculations.
- Entropy: , and from the entropy topic, for the last two pages.
- Titration, for the experiment on page 6.
Values used in these notes
| Quantity | Value |
|---|---|
| gas constant, R | 8.31 J mol⁻¹ K⁻¹ |
| pressure for | atm |
| temperature | K = °C + 273 |
| enthalpy | kJ mol⁻¹ (convert to J before dividing by T) |
| entropy | J K⁻¹ mol⁻¹ |
Reaction data such as and are given in the worked examples as they would be in an exam question. Where the data are invented, they are labelled illustrative.
How to use these notes
- Read the pages in order the first time. Later pages assume the earlier ones.
- Each page opens with its one idea in a sentence. If you can explain that sentence to someone else, you know the page.
- Coloured boxes mean the same thing on every page: definitions you may be asked to quote, key ideas, common mistakes, exam technique, and beyond the spec (interesting, but you will not be examined on it).
- Each page ends with questions and fully worked answers. Cover the answers, try the questions, then mark yourself.
- Use the topic on a page the night before an exam.
Pages
- Writing Kc
At a fixed temperature the equilibrium concentrations of a reaction always fit one expression, and the value of that expression is the equilibrium constant Kc.
- Partial pressures and Kp
For gases it is often easier to use pressures than concentrations. Each gas contributes a partial pressure, found from its mole fraction, and Kp has the same shape as Kc with partial pressures in atm.
- Heterogeneous systems
When a system has more than one phase, pure solids and pure liquids are left out of Kc and Kp, and Kp contains gases only. Check the state symbols first.
- Units of K
Kc and Kp have units that depend on the equation. Put the units into the expression and cancel, or count the coefficients. When everything cancels there are no units.
- Kc from equilibrium amounts
To calculate Kc, build a table from the starting amounts to the equilibrium amounts, convert to concentrations by dividing by the volume, then substitute. Use equilibrium values only.
- Kc from a titration
A classic experiment finds Kc by letting an ester and water reach equilibrium and then titrating the acid that formed. Subtract the blank for the acid catalyst, then use the amounts in the expression.
- Calculating Kp
For Kp, extend the table by two rows. Total the moles of gas, turn each amount into a mole fraction, multiply by the total pressure, then substitute the partial pressures.
- What changes K
At one temperature K is a fixed number. Changing a concentration, the pressure or adding a catalyst cannot change it. A change in concentration moves the mixture until the expression equals K again.
- Pressure and catalysts
Pressure moves the mixture when the moles of gas differ on each side, but it leaves Kp alone. A catalyst changes neither the mixture nor K, only how fast equilibrium is reached. Solids make no difference.
- Temperature changes K
Heating lowers K for an exothermic reaction and raises it for an endothermic one. The position of equilibrium moves because K has changed, so always explain a temperature effect through K.
- Entropy and K
The temperature dependence of K comes from entropy. Only the surroundings term, minus delta H over T, changes with temperature, and ΔS total = R ln K turns that change into a change in K.
- How far does it go
The size of K says how far a reaction goes, not how fast. A large K means mostly products, a small K mostly reactants, and K near 1 a real mixture. The page ends by explaining one tube in three ways.
Also in this topic: Topic 13 on a page
Spec checklist
Every point you can be examined on in this topic, and where it is explained. Tick them off as you go.
| Spec | You should be able to | Where |
|---|---|---|
| 13.1 | be able to deduce an expression for Kc, for homogeneous and heterogeneous systems, in terms of equilibrium concentrations | The equilibrium constant Writing the expression Homogeneous systems The same reaction, written differently Solids are left out Water as a solvent |
| 13.2 | be able to deduce an expression for Kp for homogeneous and heterogeneous systems, in terms of equilibrium partial pressures in atm | Gases share a pressure Partial pressures at equilibrium The expression for Kp Kp uses gases only |
| 13.3 | be able to calculate a value, with units where appropriate, for the equilibrium constants (Kc and Kp) for homogeneous and heterogeneous reactions, from experimental data | Put the units in and cancel A shortcut The table method When the volume cancels Starting from concentrations When the ratio is not 1 : 1 An experiment that measures K Why each step is there The calculation When only a sample is titrated The same table, two more rows When the ratio is not 1 : 1 Heterogeneous systems |
| 13.4 | understand how, if at all, a change in temperature, pressure or the presence of a catalyst affects the equilibrium composition in a homogeneous or heterogeneous system | The reaction quotient Changing a concentration Four changes at a glance Why pressure moves the mixture Adding an inert gas Catalysts Heterogeneous systems The position follows K One tube, three changes |
| 13.5 | understand that the value of the equilibrium constant is not affected by changes in concentration or pressure or by the addition of a catalyst | K belongs to a temperature Changing a concentration Four changes at a glance Catalysts |
| 13.6 | know the effect of changing the temperature on the equilibrium constant (Kc and Kp) for both exothermic and endothermic reactions | Temperature changes K |
| 13.7 | understand that the effect of temperature on the position of equilibrium is explained using a change in the value of the equilibrium constant | The position follows K One tube, three changes |
| 13.8(i) | understand the effect of a change in temperature on: the value of ΔStotal | Temperature and total entropy |
| 13.8(ii) | understand the effect of a change in temperature on: the magnitude of the equilibrium constant, since ΔStotal = R ln K | Total entropy and K The same story in one line |
| 13.9 | be able to apply knowledge of the value of equilibrium constants to predict the extent to which a reaction takes place | What the size of K tells you K and the total entropy change How far is not how fast |